Points a, b, and c are midpoints of the sides of right triangle def. which statements are true? check all that apply. (the formula for the area of a triangle is a = bh.) bc = 6 cm ac = 5 cm ba = 4 cm the perimeter of triangle abc = 12 cm. the area of triangle abc is the area of triangle def.

Given: A right triangle DEF, in which A, B,C are mid points of DE , EF, and FD respectively. BC=6 cm, AC= 5 cm, BA=4 cm

Solution:

1. Perimeter of triangle ABC=AB+BC+CA=6+5+4=15 cm

But it is given that perimeter of triangle ABC is 12 cm.So, this is incorrect statement.

2. As we know line segment joining the mid point of two sides of triangle is parallel to third side and is half of it.

AB║DF and AB=1/2 DF, BC║DE and BC=1/2 DE, AC║EF,and AC=1/2EF

∴Quad.ABCF, Quad.CBAE, Quad.DABC is a parallelogram, and diagonal of parallelogram divides it into two congruent triangles.

ΔABC≅ΔBCF≅DAC≅ABE

Area(ΔDEF)=4×Area(ΔABC)

→ Area of triangle ABC to area of triangle DEF is 1/4.

b

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.