Abasketball tournament starts with 128 teams. in each round half of the teams are eliminated how many teams remain after 5 rounds

Total number of team in starting = 128 teams.

In each round half of the teams are eliminated.

Therefore, number of teams remain after first round = 128/2 = 64.

The number of teams remain after second round = 64/2 = 32.

The number of teams remain after third round = 32/2 = 16.

The number of teams remain after fourth round = 16/2 = 8.

The number of teams remain after fifth round = 8/2 = 4.

After five rounds, only 4 teams remain.

Step-by-step explanation:

at the begginning we have 128 teams, after the first round, we have half of that, this is 128/2.

after the second round, we have half of that: (128/2)/2 = 128/(2*2)

and so on, so if n is the number of rounds, the amount of theams left can be written as:

t(n) = 128/(2^n)

and for n= 5, we have:

t(5) = 128/(2^5) = 128/32 = 4

After five rounds, only 4 teams remain.

it is c, trust i got your back lol

step-by-step explanation:

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !