The sum of three numbers is 81.the first number is 11 less than the second. the third number is 6 more than twice the first. what is the largest of the three numbers?

n - the first number

n + 11 - the second number

2n + 6 - the third number

81 - the sum of three numbers

The equation:

n + (n + 11) + (2n + 6) = 81

n + n + 11 + 2n + 6 = 81     combine like terms

(n + n + 2n) + (11 + 6) = 81

4n + 17 = 81      subtract 17 from both sides

4n = 64       divide both sides by 4

n = 16

the largest of the tree numbers is the third number 2n + 6.

Substitute the value of n:

2(16) + 6 = 32 + 6 = 38

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6