Mathematics
Mathematics, 03.07.2019 22:30, riamspmau

Sec(x+1)/tan(x) = tan(x)/sec(x-1) \frac{ \sec(x + 1) }{ \tan(x) } = \frac{ \tan(x) }{ \sec(x - 1) }

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Sec(x+1)/tan(x) = tan(x)/sec(x-1)[tex] \frac{ \sec(x + 1) }{ \tan(x) } = \frac{ \tan(x) }{ \sec(x -...

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