F(x) = -(x-3)^2+2 i need the vertex, axis of symmetry, max or min, and the range

The vertex: (3;2).

This is a parabola, the branches are directed down, then (3;2) - max.

range: E(y) = (-∞;2]

d. is the correct answer

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)