The product of two numbers is 88. the sum of the two numbers is 26. what are the numbers

let's take the numbers a and b

setup a system of equations:

a+b=26

a*b=88

now solve it using substitution:

1) b=88/a

2)(substitute) a+ 88/a = 26  

3)(add fractions) (a^2+88)/a=26

4)(get polynominal) a^2-26a+88=0

5)(factor) (a-22)(a-4)=0

6) (solve) a=22 OR a = 4

7) (after checking) a= 22 or a=4

and b=22 or b=4

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )