Which system of linear inequalities is graphed? {y> 2x+1x+y< −2 {y≥2x+1x+y≤−2 {y< 2x+1x+y> −2 {y≤2x+1x+y≥−2

y>2x+1; x+y<−2

Step-by-step explanation:

Since, dotted line represents the inequality with sign '<' or '>',

Thus, y≥2x+1; x+y≤−2  and y≤2x+1 ; x+y≥−2  can not be the system of equations,

Now, by the given graph,

The one of the related equations passes through (0, -2) and (-2, 0)

So, the equation of the related equation,

∵ Shaded region of this line does not contain the origin,

Thus, the inequality would be,

Also, other of the related equations passes through (0, 1) and (-1, -1)

So, the equation of the related equation,

∵ Shaded region of this line does not contain the origin,

Thus, the inequality would be,

y > 2x + 1

Hence, the required system would be,

y>2x+1; x+y<−2

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.