The product of two consecutive positive even intergers is 14 more than their sum. find the integers.

4 and six

Step-by-step explanation: n =  the first number  ( n + 2 ) =  the second number  

Set up an equation using the information  n ×  ( n + 2 ) = n + ( n + 2 ) + 14  doing the operations gives.  

n 2  +  2 n =  2 n  +  16  Subtract  2 n  from both sides

n 2 + 2 n −  2 n  = 2 n  − 2 n  + 16

This results in   n 2 =  16

Take the square root of both sides.

 √ n 2  =  ±  √ 16

This gives  n = 4  or  n =  − 4

The negative answer is invalid  n  =  4  add 2 to find  n + 2 ,  the second number

4 + 2 = 6

step-by-step explanation:

b and c