A, b, and c are collinear, and b is between a and c. the ratio of ab, b to ac, c is 3: 4. if a is at (-8,1) and b is at (-2,-2), what are the coordinates of point c? explain // will give brainliest

(6,-6)

Step-by-step explanation:

In order to solve this you just need to use the points given and take the separation between the coordinates and multiply them by the ratio.

Y1 is 1

Y2 is -2

The difference between this is -3, if you inster that on the ratio the answer for point C in Y would be 3:4=-3:-4

Y3 or Yc will be located -4 units away from -2 which is -6.

And now  we do the same for X

X1 is -8

X2 is -6

The difference would be +6 if we insert that on the ratio it would be 3:4=6:8

So the X on c will be located 8 units away from the x on B, -2+8=6, so the X will be located on 6

So the oredered pair of coordenate for C would be (6,-6)

f(x) = y

f(-3) = -5

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11