Mathematics

Mathematics, 04.07.2019 07:00, oliviaclerk5

Find the ratio a: b if it is given that.. $\frac{a-2b}{a+2b} =\frac{1}{2}$

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English, 24.06.2019 00:30, dayana72

What do the fourth, fifth, sixth, seventh, and eighth amendments guarantee for citizens? ability to bear arms freedom of speech a fair trial right to vote[tex]\frac{x}{y}\frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{xfdddddddddddddddddddddddddddddddd}{y}[/tex]

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Mathematics, 14.07.2019 01:30, wiintrr30

[tex] \frac{(a-3) * (\frac{a}{3} +1)}{\frac{1}{3}} [/tex] [tex] \frac{a( \frac{a}{3} ) + a - 3(\frac{a}{3}) - 3 }{\frac{a}{3}} [/tex] [tex] \frac{\frac{3a+a}{3} + a - 3 * \frac{a}{3} - 3}{\frac{1}{3}} [/tex] [tex] \frac{\frac{4a}{3} + a - a - 3}{\frac{1}{3}} [/tex] [tex] \frac{4a}{3} / \frac{1}{3} - 3 / \frac{1}{3} [/tex] [tex] \frac{4a}{3} * 3 - 3 * 3 [/tex] [tex] 4a - 9 [/tex] yet the answer i should get is [tex] a^{2}-9 [/tex]. what step am i doing wrong on this algebra problem?

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Mathematics, 30.07.2019 15:30, aaliyahmaile13

Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0 a. [tex] 0, \frac{2 \pi }{3} , \frac{4 \pi }{3} [/tex] b. [tex] \frac{ \pi }{6} , \frac{5 \pi }{6} , \frac{3 \pi }{2} [/tex] c.[tex]0, \frac{ \pi }{2}, \frac{7 \pi }{6}, \frac{11 \pi }{6} [/tex] d. no solution

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Mathematics, 01.08.2019 16:00, jedmnlp5xuks

Answer the questions 2) [tex] \frac{1}{20} \div \frac{4}{5 } = [/tex]3) [tex]10 \times \frac{1}{2} \div 3 \times \frac{1}{5 } = [/tex]4) what is the reciprocal of 4? 5) what is the reciprocal of [tex]4 \times \frac{5}{8} [/tex]6) how can you check that this is correct[tex] \frac{5}{8} \div \frac{2}{3} = \frac{15}{16} [/tex]a) [tex] \frac{15}{16} \div \frac{2}{3} = \frac{5}{8} [/tex]b)[tex] \frac{15}{16} \div \frac{5}{8} = \frac{2}{3} [/tex]c)[tex] \frac{3}{2} \times \frac{15}{16} = \frac{5}{8} [/tex]d)[tex] \frac{2}{3} \times \frac{15}{16} = \frac{5}{8} [/tex]7) [tex] \frac{3}{4} \div \frac{1}{8} = [/tex]8) [tex]9 \times \frac{3}{4} \div \frac{3}{4} = [/tex]9) all of the parts to this question is in the picture

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Find the ratio a: b if it is given that.. [tex]\frac{a-2b}{a+2b} =\frac{1}{2}[/tex]...

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