3x^2-n-4y^2=(3x-y)(x+4y),n=? need asap f.11xy g.-11xy h.13xy j.-13xy

n = -11xy, so the answer is G.

Step-by-step explanation:

3x^2−n−4y^2=(3x−y)(x+4y)

Step 1: Add -3x^2 to both sides.

3x^2−4y^2−n+−3x^2=3x^2+11xy−4y^2+−3x^2

−4y^2−n=11xy−4y^2

Step 2: Add 4y^2 to both sides.

−4y^2−n+4y^2=11xy−4y^2+4y^2

−n=11xy

Step 3: Divide both sides by -1.

n=−11xy

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

no he doesnt because "-16' is negatiive

step-by-step explanation: