Suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7,1). write an equation of the parabola in vertex from. y = -4(x-5)^2+9 y = -7(x+9)^2 - 5 y = -0.06(x-5)^2 + 9 y = -2(x+5)^2 + 9

We are given

a parabola has an axis of symmetry at x = -5, a maximum height of 9

so, we get

vertex =(-5,9)

vertex=(h,k)=(-5,9)

so, h=-5 and k=9

we can use vertex form of parabola

we can plug these value

now, it passes through the point (-7,1)

we can use it and then we can solve for a

So, we will get equation of parabola as

..............Answer