Divide x^3 -3x^2 by x-2 . step 1 - fill in the missing number:

Step-by-step explanation:

First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items

F(x) = x^3-3x^2+0x+0

We have to divide this by x-2

Leading terms in the dividend and divisor are

x^3  and x

Hence quotient I term would be x^3/x=x^2

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

Multiply x-2 by x square and write below the term and subtract

We get  

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

-x^2+0x

Again take the leading terms and find quotient is –x

                                                x-2) x^3-3x^2+0x+0(x^2-x

x^3-2x^2

-x^2+0x

                                                                  -x^2-2x

Subtract to get 2x +0 as remainder.

                                                  x-2) x^3-3x^2+0x+0(x^2-x-2

x^3-2x^2

-x^2+0x

                                                                  -x^2+2x

                                                                      -2x-0

                                                                              -2x+4

                                                                               -4

Thus remainder is -4 and quotient is x^2-x-2

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1