The question asks write an equation of the line that passes through the given point and is perpendicular to the given line. 1. (1,1); y=1/2x+4

y - 1 = -2(x - 1)

Step-by-step explanation:

We want a new line which is perpendicular to y = (1/2)x + 4.  This new line will have a slope which is the negative reciprocal of 1/2, the slope of the given line.  Thus, the slope of the perpendicular is -2.

Then, in point-slope form, the equation of the new line is:

y - 1 = -2(x - 1).

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it