Analyze the graph. determine what, if any, association there is. explain.

A scatter plot can show a linear association, a non-linear association or no association at all.

The graph shows nonlinear association

The three possible associations are as follows:

(a) Linear association

This is when the dots on the scatter plot look like they are on a straight line

(b) Nonlinear association

This is when the dots on the scatter plot appear to be in a curve.

(c) No association

This is when there is no trend between the dots of the scatter plot.

From the explanation above, and a proper observation of the given graph, we can conclude that the graph shows a nonlinear association.

See attachment for scatter plot associations

Read more about scatter plot associations

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From the scatter plot we may observe that the data points follow a parabolic path.Hence, the association between the points is non-linear also, the data points follow a quadratic association.

Also, when we make a quadratic curve around these data points we see that all of the data points will be closely related to the curve.

Hence, there is a strong association between the data points.

true

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.