In a parallel circuit, et = 240 v, r = 330 ω, and xl = 420 ω. what is z?

Z = 258Ω

Step-by-step explanation:

There are two methods of solving this question,

First method

Z = ( RXL)/ sqr rt ( R²+XL²)

Z= (330 Ω × 420 Ω)/ sqr rt ( 330 Ω² + 420 Ω²)

Z = 138600 Ω /534

Z = 259  Ω

THE second complete method is given in attachment below

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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