The rectangle below has an area of 7b^2+14b square meters. the width of the rectangle (in meters) is equal to to the greatest common monomial factor of 7b^2 and 14b. what is the length and width of the rectangle?

L = b + 2.

W = 7b

Step-by-step explanation:

Factoring 7b^2 and 14b, we get 7b(b + 2).  The greatest common monomial factor here is 7b.  This is the width of the rectangle in question.

The area of the rectangle is 7b^2+14b.

Obtain the length of the rectangle by dividing 7b^2+14b by 7b:

L = b + 2.

W = 7b

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

7

step-by-step explanation:

the answer would be 7