Starting from 1.4 miles away a car drives towards a speed check point and then passes it the car travels at a constant rate of 52 miles per hour the distance of the car from the check point is given by d=1.4-52t at what times is the car 0.6 miles from the check point

At t=0.015 hours when the car 0.6 miles from the check point.

Step-by-step explanation:

Since we have given that

Distance traveled by him towards a speed check point = 1.4 miles

Speed at which he is travelling = 52 miles per hour

Let the time taken by him be x

Since we have the equation

where d denotes distance

and t denotes time.

If we have given that the car 0.6 miles from the check point.

So, we put the value of d in place of it .

So, at t=0.015 hours when the car 0.6 miles from the check point.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )