Mathematics

Mathematics, 04.07.2019 22:30, SuBzErO24

What is the square root of negative 40

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Mathematics, 23.07.2019 06:00, minersaysay22

Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 − 3 = x square root of negative 2x plus 1 − 3 + 3 = x + 3 square root of negative 2x plus 1 = x + 3 square root of negative 2x plus 1 − 1 = x + 3 − 1 square root of negative 2 x = x + 2 ( square root of negative 2 x )2 = (x − 4)2 −2x = x2 − 8x + 16 −2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16 0 = (x + 2)(x + 8) x + 2 = 0 x + 8 = 0 x + 2 − 2 = 0 − 2 x + 8 − 8 = 0 − 8 x = −2 x = −8 both solutions are extraneous because they don't satisfy the original equation. what error did eloise make?

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Mathematics, 02.08.2019 21:00, madisonmoore9716

Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 − 3 = x square root of negative 2x plus 1 − 3 + 3 = x + 3 square root of negative 2x plus 1 = x + 3 square root of negative 2x plus 1 − 1 = x + 3 − 1 square root of negative 2 x = x + 2 ( square root of negative 2 x )2 = (x − 4)2 −2x = x2 − 8x + 16 −2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16 0 = (x + 2)(x + 8) x + 2 = 0 x + 8 = 0 x + 2 − 2 = 0 − 2 x + 8 − 8 = 0 − 8 x = −2 x = −8 both solutions are extraneous because they don't satisfy the original equation. what error did eloise make?

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Mathematics, 14.09.2019 17:10, kayliehernandez

This is a easy question me asap ! < 3 question order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6 answer choices negative 31 over 6, negative square root 26, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative 31 over 6, negative square root 26 negative square root 26, negative 31 over 6, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative square root 26, negative 31 over 6

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Mathematics, 30.10.2019 07:31, makaleyf19

Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 − 3 = x square root of negative 2x plus 1 − 3 + 3 = x + 3 square root of negative 2x plus 1 = x + 3 square root of negative 2x plus 1 − 1 = x + 3 − 1 square root of negative 2 x = x + 2 (square root of negative 2 x)2 = (x − 4)2 −2x = x2 − 8x + 16 −2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16 0 = (x + 2)(x + 8) x + 2 = 0 x + 8 = 0 x + 2 − 2 = 0 − 2 x + 8 − 8 = 0 − 8 x = −2 x = −8 both solutions are extraneous because they don't satisfy the original equation. what error did eloise make?

Answers: 1

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