Line ab passes through points a(-6,6) and b(12, 3) if the equation of the line is written in slope-intercept form, y then m1 and b mx+ b, then m=-1/6 and b =?

The value of b is 5.

Step-by-step explanation:

Given: Line AB passes through points A(-6,6) and B(12,3).

Slope- intercept form:-The equation of a line with slope m and making an intercept b on y -axis is y = mx + b.

Since the line passes through two points therefore, we can use the Two Point Form formula:

; where m is the slope.

or Slope

First find the value of m using the points A(-6,6) and B(12,3) ;

Now, the equation of line AB :-

or

or

 or

Simplify:

Comparing above equation with the general equation of line i.e, y = mx+b , we get;

and b= 5

Therefore, the value y-intercept (b) = 5

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)