The solution for x2 + 2x + 8 ≤ 0 is a) all real numbers b) the empty set c) x= 2 or x =4 d) x = -2 or x = 4

Step-by-step explanation:

Please use " ^ " for exponentiation:  x^2 + 2x + 8 ≤ 0.

Let's solve this by completing the square:

x^2 + 2x + 8 ≤ 0  =>  x^2 + 2x + 1^2 - 1^2 + 8 ≤ 0.  Continuing this rewrite:

                                    (x + 1)^2 + 7 ≤ 0

Taking the sqrt of both sides:   (x + 1)^2 = i*sqrt(7)

Then the solutions are x = -1 + i√7 and x = -1 - i√7

There's something really wrong here.  I've graphed your function, x^2 + 2x + 8, and can see from the graph that there are no real roots, but only complex roots.  Please double-check to ensure that you've copied down this problem correctly.

256π units²   (answer b)

step-by-step explanation:

the formula for the surface area of a sphere of radius r

is             a = 4πr²

and so, if r = 8 units, then the surface area is:

a = 4π(8 units)² = 256π units²   (answer b)

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540