In january, bangkok is hotter than cape town while cape town is hotter than moscow. which inequality correctly compares the temperatures of the three cities? a. bangkok's temperature < cape town's temperature < moscow's temperature b. bangkok's temperature < moscow's temperature < cape town's temperature c. bangkok's temperature > moscow's temperature > cape town's temperature d. bangkok's temperature > cape town's temperature > moscow's temperature

The correct option is D.

Explanation:

It is given that in January, Bangkok is hotter than Cape Town it means the temperature of Bangkok is greater than the temperature of Cape Town. It can be written in the inequality form as shown below,

Bangkok's temperature > Cape Town's temperature

It is the conclusion (1).

It is also given that the Cape Town is hotter than Moscow it means the temperature of Cape Town is greater than Moscow. It can be written in the inequality form as shown below,

Cape Town's temperature > Moscow's temperature

It is the conclusion (2).

When we combine conclusion (1) and (2). We get

Bangkok's temperature > Cape Town's temperature > Moscow's temperature

This statement is shown in option D, therefore the correct option is D.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

idk

step-by-step explanation:

i don't know