Due! extra points! how many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 60% antifreeze? use the six-step method! brainliest answer included

Ok, let’s take it step by step.
Let x = number of gallons of 70% solution
100 = number of gallons of 25% solution
Then x + 100 = number of gallons of a 60% solution.

0.70x + 0.25(100) = 0.60(x + 100)

0.70x + 25 = 0.60x + 60

0.10x = 35

x = 350 gal

So, you can mix 350 gal of a 70% solution with 100 gal of a 25% solution to get 450 gallons of a 60% antifreeze solution.

It is a percent with money involved too divide and you should have your answer

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2