Julie and eric row their boat (at a constant speed) 18 miles downstream for 3 hours by the current. rowing at the same rate, the trip back against the current takes 6 hours. find the rate of the boat in still water.

Answer

Find out the the rate of the boat in still water.

To proof

let us assume that the speed of the boat in the still water = u

let us assume that the speed of the current = v

Formula

As given

18 miles downstream for 3 hours

Now for the downstream

u + v = 6

now for the upstream

As given

the trip back against the current takes 6 hours

u-v = 3

Than the two equation becomes

u + v = 6 and u - v = 3

add both the above equation

we get

2u = 9

u = 4.5miles per hour

put this in the  u - v = 3

4.5 -v = 3

v =1.5 miles per hour

The rate of  the boat in the still water is  4.5miles per hour .

Hence proved

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)