Three watermelons and two cantaloupes weigh 32 pounds. four watermelons and three cantaloupes weigh 44 pounds. all watermelons weigh the same amount, and all cantaloupes weigh the same amount. what is the weight of the two watermelons and one cantaloupe? plz answer i will give you 100 points

A melon weighs 8 pounds and a cantaloupe weighs 4 pounds

So weight of the 2 melons and 1  cantaloupe =   2(8)+4 = 20 pounds

Step-by-step explanation:

4m + 3c =  44       where m = melons and c = cantaloupes (weight of)

3m + 2c = 32

Multiply first equation by 2 and second by -3:-

8m + 6c = 88

-9m - 6c = -96

Adding:-

-m = -8

m = 8

and 3c =  44- 4(8) = 12  (from the first equation)

c = 4

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation:

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.