What is the interquartile range (iqr) of the following data set 17 16 21 15 25 22 18 23 17

IQR = 6

First locate the median at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles and located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

= 18

= = 16.5

= = 22.5

IQR = - = 22.5 - 16.5 = 6

it has the same slope and a different y-intercept

hope this : )

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.