Calculate the difference scores for the following data from a repeated measures study. conduct a repeated measures t-test at aplha=.05 to find whether there was a change in scores. subject a: pre test score=34 post test score=39. subject b: pre test score=41, post test score=48. subject c: pre test score=38, post test score=35. subject d: pre test score=29, post test score=36

There is no difference as per statistical evidence.

Step-by-step explanation:

We calculate t statistic from the formula

t =difference in means/Std error of difference

Here n1 = n2

t = (x bar - y bar)/sq rt of s1^2+s2^2

Let treatment I =X = 34 41 38 29

     Treatment II Y = 39 48 35 36

                     X       Y    

Mean          35.50   39.50

Variance     81.00   105.00

H0: x bar = y bar

Ha: x bar not equal to y bar

(Two tailed test at 0.05 significant level)

N1 = 4 and N2 = 4

df=N1+N2-2 = 6

s1^2 = 81/3 =27 and s2^2 = 105/3 = 35

Std error for difference =

t = -1.02

p =0.348834

p>0.05

Since p value >alpha we accept null hypothesis.

Hence there is statistical evidence to show that there is no difference in the mean level of scores.  

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

96 39 cause 135 -96=39 im smart (i used a calculater)