Abaseball is thrown straight upward with an initial speed of 64 ft/sec. the number of feet s above the ground after t seconds is given by the equation x16+641. at what times will the baseball be 48 ft above the ground?

We are given

A baseball is thrown straight upward with an initial speed of 64 ft/sec

and

The number of feet s above the ground after t seconds is given by the equation -16t^2 +64t

so, we get

we can set s(t)=48

and then we can solve for t

we can factor out 16

divide both sides by 16

and we get

we can multiply both sides by -1

now, we can factor it

So, the baseball be 48 ft above the ground at 1 sec and 3 sec.......Answer

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )