Luis wants to buy a skateboard that costs $89.99. he has $30 saved. he wants to save $11 each week until he has enough money to pay for the skateboard. the inequality 30+11w ≥89.99 30+11w ≥89.99 where w is the number of weeks, represents this situation. what is the least number of weeks luis has to save until he has enough money to pay for the skateboard?

You want to take 11 and multiply 11 by 6 and get 66. Then add 66 and 30 and get 96. That's more then enough for the skateboard. 5 weeks will only equal 85, so 6 weeks is the least you can do.

-Edge

answer:     true

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.