One number is 11 more than twice another number. if the sum of the numbers is twice their difference, find the numbers.

So, we need to make some equations to find this.

Let x be "one number"

x = (2y) +11

x+y = 2(x-y)

Now we can substitute

2y+11 +y = 2(2y+11)-2y

3y+11 = 4y+22-2y

3y+11 = 2y+22

y+11 = 22

y= 11

So the "Other number" is equal to 11.

Now, we can solve for x

x = 2y+11

x = 2(11) + 11

x = 22+11

x = 33

So, the numbers are 33 and 11

b. x- 48 =120

step-by-step explanation:

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step-by-step explanation: