Araindrop drops from a window ledge of a building. the window ledge is 80 feet above the ground. how long does it take before the drop passes by another window ledge that is 16 feet above the ground?

It takes 2 seconds before the drop passes through another window ledge that is 16 ft above the ground.

Step-by-step explanation:

The formula to find time is

Here the drop falls from a window which at a height of 80 ft.

Hence the initial velocity = 0 = u

Now when it passes through a widow at a height of 16 ft, it has covered a distance of = 80-16 = 64 ft = d

It is falling under the gravity so its acceleration = g = 9.8 m/s² = 32 ft /s²

Substituting the values in the formula we get

Dividing both sides by 16 we get

Taking square root on both sides we get

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%