Explain how you found the gfc of 12a^2 b^6, 28a^4, and 42ab^3

4a

Step-by-step explanation:

12a²b⁶                         28a⁴                          42ab³

 ∧    ∧                           ∧  ∧                          ∧   ∧

2  6  a² b⁶                    7 4                   7 6 a b³

   ∧     ∧                          ∧                              ∧     ∧

  2 3  aa          2 2                           2 3   bbb

12a²b⁶: 2 * 2 * 3 * aa *

28a⁴: 2 * 2 * 7 *

42ab³: 2 * 2 * 3 * 7 * a * bbb  

What do they have in common? two 2s and one a  

GCF = 2 * 2 * a = 4a          

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.