Anyone have the answer to this? need asap?

For this case we have the following data:

Polynomial function of grade 5

Given roots: -2, 2,

Having an imaginary root given by , the other root, in the same imaginary way, must be given by its complex conjugate, that is, .

In this way, the fourth root is given by:

Since the polynomial function is grade 5, it must have 5 roots. Thus, the fifth root must be given by a real number.

Thus, the roots of the polynomial function are given by: three real roots and two imaginary roots.

Option D

f(x) has 3 real roots x = -2, x = 2 and x = 4

complex roots occur in conjugate pairs

x = i is a root then x = - i is a root

there are therefore 2 imaginary roots

f(x) has 3 real roots and 2 imaginary roots

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

6e14 is the answer.