What is the product (y+3)(y^2-3y+9)

y^3 + 3^3

Step-by-step explanation:

1) Multiply each term of (y^2-3y+9) by y:  y^3 - 3y^2 + 9y

2) Multiply each term of (y^2-3y+9) by 3:  3y^2 - 9y + 27

3) Add all of these terms together:  y^3 + 27 = y^3 + 3^3

Note:  this is an example of 'special products and factoring.'

-14 is the answer

hope this : ))