Eliza’s backpack weighs 18 7/9 pounds with her math book in it. without her math book, her backpack weighs 14 ⅞ pounds. how much does eliza’s math book weigh?

The Eliza's math book weigh = .

Step-by-step explanation:

We are given that

Eliza's backpack weighs with her math book  =

Eliza's backpack weighs without her math book=

We have to find the Eliza's math book weigh.

Therefore, we subtract the Eliza's backpack weighs without her math book from the Eliza's backpack weighs with her math book.

Eliza's math book weighs= Eliza's backpack weighs with her math book - Eliza's backpack weighs without her math book

Eliza's math book weighs =

Eliza's math book weighs=

Eliza's math book weighs=

Eliza's math book weighs=

Eliza's math book weighs=

Hence, the Eliza's math book weighs=.

answer: what if i dont want to show my work boi.

step-by-step explanation: im watching dbz and eating popcorn leave meh alone

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!