If (2 − 3i) + (x + yi) = 6, what is x + yi?

(2 − 3i) + (x + yi) = 6

We add the left hand side

(2+x) + (-3+y)i = 6

6 can be written in a+ib

6 can be written as 6 + 0i

(2+x) + (-3+y)i = 6 +0i

Now we frame 2 equations

2 + x= 6

-3 + y =0

Solve the first equation

2 + x = 6

Subtract 2 from both sides

x = 4

solve the second equation

-3 + y =0

Add 3 on both sides

y= 3

So x+yi is 4+3i

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: