Mathematics, 06.07.2019 02:00, pacpac1172

Atea that is 22% jasmine is blended with a tea that is 13% jasmine. how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine

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answered: leroybennett06

Given

A tea that is 22% jasmine is blended with a tea that is 13% jasmine

Find out the how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.

To proof

Let us assume that the a tea that is 22% jasmine is blended = a

Let us assume that the a tea that is 13% jasmine is blended = b

Total amount of tea made = 10lb

the equation be

a + b = 10

as given

jasmine tea are used to make 10lb of tea that is 19.3% jasmine.

write 22% in the decimal form

$= \frac{22}{100}$

= 0.22

write 13% in the decimal form

$=\frac{13}{100}$

= 0.13

write 19.3% in the decimal form

$=\frac{19.3}{100}$

= 0.193

than the equation be

0.22a + 0.13b = 0.193 × 10

on simplify

22a + 13b = 193

two equation becomes

22a + 13b = 193 and a + b = 10

multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193

we get

22a - 13a + 13b -13b = 193 - 130

9a = 63

a = 7lb

put this value in the a + b = 10

we get

7 + b = 10

b = 3lb

Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .

Hence proved

answered: Guest

$3 \times 4 = 12 \\ 6 \times 8 = 48$ $48 + 12 = 60$ hope it is correct if not i'm srry i tried to

answered: Guest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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Atea that is 22% jasmine is blended with a tea that is 13% jasmine. how many pounds of the 22% jasmi...