Asalvage ship’s sonar locates wreckage at a 12 degree angle of depression. a diver is lowered 40 meters to the ocean floor. how far does the diver need to walk along the ocean floor to the wreckage? 188.2 units 8.5 m 192.4 m 41.0 m

The diver need to walk 188.2m along the ocean floor to the wreckage.

Step-by-step explanation:

Check the attachment for diagram.

Using SOH, CAH TOA to get the distance the diver need to walk along the ocean floor to the wreckage,

Note that the angle is a right angled triangle with the height of the triangle being the opposite side and the distance needed as the adjacent side.

Using TOA

Tan(theta) = Opposite/Adjacent

Given theta = 12°

Opposite = 40m

Adjacent side = x

Tan12° = 40/x

x = 40/tan12°

x = 188.2m

77

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18