The perimeter of a rectangle is 280 meters. the width is 26 meter less than the length . fun the length and width.( show work)

The length is 83 meters. The width is 57 meters.

Step-by-step explanation:

We have two unknowns, the length and the width.

Let L = length.

The width is 26 meters less than the length, so the width is L - 26.

The perimeter of a rectangle is the sum of two lengths and two widths.

P = L + L + W + W

Now we replace P with the given perimeter; L remains L ans the unknown; we replace W with L - 26.

280 = L + L + L - 26 + L - 26

We solve for L.

280 = 4L - 52

332 = 4L

4L = 332

L = 83

The length is 83 meters.

The width is 26 meters less than the length, so

W = L - 26 = 83 - 26 = 57

The width is 57 meters.

Check: Add two lengths and two widths and see if you get 280 meters.

83 m + 83 m + 57 m + 57 m = 280 m

Also, check the difference: 83 m - 57 m = 26 m

Both conditions are true, so our answer is correct.

47 - 90 = 43

43 - 180 = x

x = 137