The length of a rectangle is triple the width. it's perimeter is more than 40m. find the smallest possible values for its length and width.

Given:- the length of a rectangle is triple the width. it's perimeter is more than 40m.

Now, from the given condition we have , where l is the length of the rectangle and b is the width of the rectangle.

Perimeter(P) of a rectangle is given by,

Since perimeter is more than 40 m we have,

8b>40

⇒ b>5 m

since, then

⇒

if we take the integers, the smallest possible values for its length and width , m and b=6 m.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: