What are the x and y intercepts for the equation 16x-4y=2? ? need answers asap worth

x-intercept = 1/8

y-intercept = -1/2

Step-by-step explanation:

Let y = 0, and solve for x to find the x-intercept. Then let x = 0 and solve for y to find the y-intercept.

x-intercept

16x - 4y = 2

16x - 4(0) = 2

16x - 0 = 2

16x = 2

x = 2/16

x = 1/8

x-intercept = 1/8

y-intercept

16x - 4y = 2

16(0) - 4y = 2

0 - 4y = 2

-4y = 2

y = 2/-4

y = -1/2

y-intercept = -1/2

-9

step-by-step explanation:

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x