Look at the ! brainliest and 5 star to the quickest right answer guys ive been doing homework all weekend and this is the last question end my sufferning b(1)=−2 b(n)=b(n−1)−7 find the 3rd term

-16

Step-by-step explanation:

Here, we have to use the general term to find the third term.

Given,

nth term is

b(n)=b(n-1)-7

Using   n=2, we get

b(2)=b(2-1)-7

    =b(1)-7

we are given      b(1)=-2

So,   b(2)=-2-7

             =-9

Now, using   n=3  in the nth term we get

b(3)=b(3-1)-7

    =b(2)-7

using    b(2)=-9 from above we get

b(3)=-9-7

    =-16

So, the 3rd term is    -16

Hey there!!

Given is an recursive formula :-

... b(n) = b(n-1) - 7

In this equation, 'n' is the number of the term we will need to find and '-7' is the common difference.

... b(1) = -2

We get to know that the first term is -2.

Now, we will find the 2nd term :-

... b(2) = b(2-1) - 7

... b(2) = b(1) - 7

We know b(1) is -2.

... b(2) = -2-7

... b(2) = -9

The second terms is -9 b(2) = -9

Now, let's find the third term :-

... b(3) = b(3-1) - 7

... b(3) = b(2) - 7

We know b(2) is -9

... b(3) = -9-7

... b(3) = -16

The third terms is -16.

Hence, the third term and the answer is -16.

Hope my answer helps!!

correct answer:

b.(19,-2)

any options?

step-by-step explanation: