Write 6(x – 5)4 + 4(x – 5)2 + 6 = 0 in the form of a quadratic by using substitution. a. 6u2 + 4u + 6 = 0, where u = x – 5 b. 6u2 + 4u + 6 = 0, where u = (x – 5)2 c. 6u4 + 4u + 6 = 0, where u = x – 5 d.6u4 + 4u + 6 = 0, where u = (x – 5)2the answer is  b. 6u2 + 4u + 6 = 0, where u = (x – 5)2 

We are given the equation:

..........(1)

Now we have to write it in quadratic form using substitution.

The general form of quadratic equation is given by:

So let us say

.......(2)

Plugging the value of (x-5)² from equation (2) in (1),

Answer : Option B.

the least common denominator is 40

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step-by-step explanation: