Mathematics

Mathematics, 06.07.2019 07:30, Ezekielcassese

Enter the rational number a/b where a and b are integers 3 1/2

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Mathematics, 30.06.2019 18:30, someone2301

Why is the sum of two rational numbers always rational? select from the options to correctly complete the proof. \ let / and / represent two rational numbers. this means a, b, c, and d are (integers, natural numbers, imaginary numbers), and b is not (zero, rational, negative) and d is not (zero, rational, negative). the product of the numbers is / where bd is not 0. because integers are closed under (addition, subtraction, multiplication, division), / is the ratio of two integers making it a rational number.

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Mathematics, 11.07.2019 09:00, ZVSaniya0420

Let’s say x is an irrational number and y is a rational number. the rational number y can be written as y=a/b, where a and b are integers and b=0. leave the irrational number x as x since it can’t be written as the ratio of two integers. prove the hypothesis using proof by contradiction. in other words try to show that x+y equals a rational number instead of an irrational number. let the sum equal m/n where m and n are integers and n=0. plug in the values to get this equation x+a/b=m/n. solve for the equation for x

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Mathematics, 13.07.2019 03:30, Weser17

Fill in the blanks of the following proof by contradicition that 7 + 4√2 is an irrational number. (you may use the fact that √2 is irrational.) proof: suppose not. that is suppose that 7 + 4√2 is (i) by definition of rational, 7 + 4√2 = a/b, where (ii) multiplying both sides by b gives 7b + 4b√2 = a so if we subtract 7b from both sides we have 4b√2 = (iii) dividing both sides by 4b gives √2 = (iv) but then √2 would be rational number because (v) this contradicts our knowlegde that √2 is irrational. hence the supposition is false and the given statement is true. a. (i). rational (ii). a and b are integers and b cannot equal 0 (iii). a+7b (iv). (a+7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number. b. (i). irrational (ii). a and b are integers and b cannot equal 0 (iii). a-7b (iv). (a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a irrational number. c. (i). irrational (ii). a and b are integers and b cannot equal 0 (iii). a-7b ( a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number. d. b. (i). rational (ii). a and b are integers and b cannot equal 0 (iii). a-7b ( a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number.

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Engineering, 15.10.2019 22:20, juliashalnev

Write a method ismultiple that determines, for a pair of integers, whether the second integer is a multiple of the first. the method should take two integer arguments and return true if the second is a multiple of the first and false otherwise. [hint: use the remainder operator .] incorporate this method into an application that inputs a series of pairs of integers (one pair at a time) and determines whether the second value in each pair is a multiple of the first.har() prompts: enter a second number: enter one number: sample outputs : enter one number: enter a second number: 49 is a multiple of 7 do you want to enter another pair(y/n)? enter one number: enter a second number: 28 is a multiple of 7 do you want to enter another pair(y/n)? enter one number: enter a second number: 42 is a multiple of 7 do you want to enter another pair(y/n)? enter one number: enter a second number: 7 is not a multiple of 42 do you want to enter another pair(y/n)? enter one number: enter a second number: 25 is a multiple of -5 do you want to enter another pair(y/n)? enter one number: enter a second number: 12 is a multiple of -12 do you want to enter another pair(y/n)? enter one number: enter a second number: 9 is not a multiple of 56 do you want to enter another pair(y/n)?

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