Solve |y + 2| > 6 i dont understand this,

y < - 8  or y > 4

inequalities of the form | x | > a always have solutions of the form

x < - a or x > a

we have to solve

y + 2 < - 6 or y + 2 > 6

y + 2 < - 6 ( subtract 2 from both sides )

y < - 8

or

y + 2 > 6 ( subtract 2 from both sides )

y > 4

these can be combined using interval notation

y ∈ (- ∞, - 8 ) ∪ (4, ∞ )

As a check

substitute chosen values of x from each interval

y = - 10 :  | - 10 + 2 | = | - 8 | = 8 > 6 this is true

y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12

1. perpendicular

2. parallel

3. perpendicular