You! you have 29 coins consisting of quarters and dimes. the number of dimes is 5 more than three times the number of quarters. how many dimes do you have? how many quarters do you have?

let x be the number of quarters, and y be the number of dimes.

we know that x + y = 29

then we are also given that

y = 5 + 3x

so we can solve for x and y:

plug y into the first equation:

x + 5 + 3x = 29

4x = 24

x = 6

and

y = 5 + 3*6 = 23

I have 6 quarters and 23 dimes

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!