Important! will vote ! in the following formula, vi is initial velocity, ve is ending velocity, a is acceleration, and d is distance. if vi is 7 meters per second, a is 8 meters per second squared, and d is 2 meters, what is the value of ve?

The value of the ve = 9m/sec

Step-by-step explanation:

From the given formula, it can be conclude that this is evenly accelerated movement.

First I will rewrite given formula

vi = √ ve∧2 - 2ad   First we will square on both sides and get

vi∧2 = ve∧2 - 2ad Now we will add monom (+2ad) to both sides and get

vi∧2 + 2ad = ve∧2 -2ad + 2ad =>

ve∧2 = vi∧2 +2ad  Now we will rooted both sides and get

ve = √vi∧2 + 2ad  

Now we will replace given data vi=7m/sec, a=8m/s∧2 and d=2m in the last formula

ve= √7∧2 + 2*8*2 = √49+32 = √81 = 9

ve= 9m/sec

Good luck!!!

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula