Jerrica is selling calendars to raise money for a community group she belongs to. a basic calendar sells for $10 and a deluxe calendar sells for $15. the number of deluxe calendars jerrica sells must be greater than or equal to 3 times the number of basic calendars she sells. she has at most 72 calendars to sell. the number of basic calendars sold is represented by x and the number of deluxe calendars sold is represented by y. what is the maximum revenue she can make? a. $810 b. $990 c. $1080 d. $1296

The correct answer is option B.

Let the basic calendars be = x

Let the deluxe calendars be = y

Total calendars are = 72 , so equation becomes:

 .............(1)

Cost of 1 basic calendar = $10

So, cost of all basic calendars will be = 10x

Cost if 1 deluxe calendar = $15

So, cost of all deluxe calendars = 15y

As given, the number of deluxe calendars must be greater than or equal to 3 times the number of basic calendars, the equation becomes

y=3x ...............(2)

Putting the value of y from (2) in (1)

x=18

As, y=3x

y=

So we have 18 basic calendars and 54 deluxe calendars.

Cost of 18 basic calendars will be=

Cost of 54 deluxe calendars will be =

So total amount is = $990

Hence, the maximum revenue is $990.

step-by-step explanation: