Izzy is iago's little sister. she is counting her coins. izzy finds that she has three more quarters ($0.25) than she has dimes ($0.10), twice as many nickels ($0.05) as she has dimes, and four times as many pennies ($0.01) as she has dimes. with a total of $7.61 in coins, how many coins of each type does izzy have?

Lzzy has three more quarters ($0.25) than she has dimes ($0.10), twice as many nickels ($0.05) as she has dimes, and four times as many pennies ($0.01) as she has dimes.

Let us assume number of dimes = x.

"Three more quarters than dimes" would be = (x+3) quarters .

"Twice as many nickels as dimes " would be = (2x) nickels.

"Four times as many pennies as dimes" would be =(4x) pennies.

Total value of all coins = $7.61.

We can setup an equation now.

0.10*x + 0.25(x+3) + 0.05(2x)+0.01(4x)=7.61.

Let us simplify the equation.

0.10x + 0.25x + 0.75 + 0.10x + 0.04x = 7.61

0.49x + 0.75 = 7.61.

Subtratcing 0.75 from both sides, we get

0.49x = 6.86

Dividing both sides by 0.49, we get

x= 14.

Therefore,

answer: ask

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)