The equation y-5=6(x+1) is written in point-slope form. what is the equation written in slope-intercept form? y = 6x + 11y = 6x – 1 y = 6x – 4y = 6x + 6

The slope-intercept form: y = mx + b

We have in point-intercept form: y - 5 = 6(x + 1)

Transform:

y - 5 = 6(x + 1)     |use distributive property

y - 5 = (6)(x) + (6)(1)

y - 5 = 6x + 6     |add 5 to both sides

y = 6x + 11

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36